This section of the tutorial MySQL looks at the In and BETWEEN operators.
To list employees who are Web Designers and System Administrators, we use a SELECT statement as
SELECT f_name, l_name, title from
-> employee_data where
-> title = 'Web Designer' OR
-> title = 'System Administrator';
+---------+--------+----------------------+
| f_name | l_name | title |
+---------+--------+----------------------+
| Anamika | Pandit | Web Designer |
| Mary | Anchor | Web Designer |
| Roger | Lewis | System Administrator |
| Danny | Gibson | System Administrator |
+---------+--------+----------------------+
4 rows in set (0.01 sec)
SQL also provides an easier method with IN. Its usage is quite simple.
SELECT f_name, l_name, title from
-> employee_data where title
-> IN ('Web Designer', 'System Administrator');
+---------+--------+----------------------+
| f_name | l_name | title |
+---------+--------+----------------------+
| Anamika | Pandit | Web Designer |
| Mary | Anchor | Web Designer |
| Roger | Lewis | System Administrator |
| Danny | Gibson | System Administrator |
+---------+--------+----------------------+
4 rows in set (0.00 sec)
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Suffixing NOT to IN will display data that is NOT found IN the condition. The following lists employees who hold titles other than Programmer and Marketing Executive.
SELECT f_name, l_name, title from
-> employee_data where title NOT IN
-> ('Programmer', 'Marketing Executive');
+---------+----------+----------------------------+
| f_name | l_name | title |
+---------+----------+----------------------------+
| Manish | Sharma | CEO |
| John | Hagan | Senior Programmer |
| Ganesh | Pillai | Senior Programmer |
| Anamika | Pandit | Web Designer |
| Mary | Anchor | Web Designer |
| Hassan | Rajabi | Multimedia Programmer |
| Paul | Simon | Multimedia Programmer |
| Arthur | Hoopla | Multimedia Programmer |
| Kim | Hunter | Senior Web Designer |
| Roger | Lewis | System Administrator |
| Danny | Gibson | System Administrator |
| Mike | Harper | Senior Marketing Executive |
| Shahida | Ali | Customer Service Manager |
| Peter | Champion | Finance Manager |
+---------+----------+----------------------------+
14 rows in set (0.00 sec)
BETWEEN is employed to specify integer ranges. Thus instead of age >= 32 AND age <= 40, we can use age BETWEEN 32 and 40.
select f_name, l_name, age from
-> employee_data where age BETWEEN
-> 32 AND 40;
+---------+------------+------+
| f_name | l_name | age |
+---------+------------+------+
| John | Hagan | 32 |
| Ganesh | Pillai | 32 |
| John | MacFarland | 34 |
| Alok | Nanda | 32 |
| Hassan | Rajabi | 33 |
| Arthur | Hoopla | 32 |
| Kim | Hunter | 32 |
| Roger | Lewis | 35 |
| Danny | Gibson | 34 |
| Mike | Harper | 36 |
| Shahida | Ali | 32 |
| Peter | Champion | 36 |
+---------+------------+------+
12 rows in set (0.00 sec)
You can use NOT with BETWEEN as in the following statement that lists employees who draw salaries less than $90000 and more than $150000.
select f_name, l_name, salary
-> from employee_data where salary
-> NOT BETWEEN
-> 90000 AND 150000;
+---------+------------+--------+
| f_name | l_name | salary |
+---------+------------+--------+
| Manish | Sharma | 200000 |
| Mary | Anchor | 85000 |
| Fred | Kruger | 75000 |
| John | MacFarland | 80000 |
| Edward | Sakamuro | 75000 |
| Alok | Nanda | 70000 |
| Paul | Simon | 85000 |
| Arthur | Hoopla | 75000 |
| Hal | Simlai | 70000 |
| Joseph | Irvine | 72000 |
| Shahida | Ali | 70000 |
+---------+------------+--------+
11 rows in set (0.00 sec)
