Possible Answers

  1. mysql> SELECT f_name, l_name, salary 
        -> from employee_data 
        -> ORDER BY salary;
        
    +---------+------------+--------+
    | f_name  | l_name     | salary |
    +---------+------------+--------+
    | Alok    | Nanda      |  70000 |
    | Hal     | Simlai     |  70000 |
    | Shahida | Ali        |  70000 |
    | Joseph  | Irvine     |  72000 |
    | Fred    | Kruger     |  75000 |
    | Edward  | Sakamuro   |  75000 |
    | Arthur  | Hoopla     |  75000 |
    | John    | MacFarland |  80000 |
    | Mary    | Anchor     |  85000 |
    | Paul    | Simon      |  85000 |
    | Anamika | Pandit     |  90000 |
    | Hassan  | Rajabi     |  90000 |
    | Danny   | Gibson     |  90000 |
    | Monica  | Sehgal     |  90000 |
    | Roger   | Lewis      | 100000 |
    | Ganesh  | Pillai     | 110000 |
    | Kim     | Hunter     | 110000 |
    | John    | Hagan      | 120000 |
    | Mike    | Harper     | 120000 |
    | Peter   | Champion   | 120000 |
    | Manish  | Sharma     | 200000 |
    +---------+------------+--------+
    21 rows in set (0.00 sec)
    
    
  2. mysql> SELECT f_name, l_name, yos
        -> from employee_data
        -> ORDER by yos;
        
    +---------+------------+------+
    | f_name  | l_name     | yos  |
    +---------+------------+------+
    | Arthur  | Hoopla     |    1 |
    | Danny   | Gibson     |    1 |
    | Mary    | Anchor     |    2 |
    | Edward  | Sakamuro   |    2 |
    | Paul    | Simon      |    2 |
    | Kim     | Hunter     |    2 |
    | Roger   | Lewis      |    2 |
    | Mike    | Harper     |    2 |
    | Hal     | Simlai     |    2 |
    | Joseph  | Irvine     |    2 |
    | Anamika | Pandit     |    3 |
    | Fred    | Kruger     |    3 |
    | Alok    | Nanda      |    3 |
    | Hassan  | Rajabi     |    3 |
    | Monica  | Sehgal     |    3 |
    | Shahida | Ali        |    3 |
    | Manish  | Sharma     |    4 |
    | John    | Hagan      |    4 |
    | Ganesh  | Pillai     |    4 |
    | John    | MacFarland |    4 |
    | Peter   | Champion   |    4 |
    +---------+------------+------+
    21 rows in set (0.01 sec)
    
    
  3. The statement displays the ids, last names, titles and ages of all employees sorted on titles in descending order and age in ascending order.
    mysql> SELECT emp_id, l_name, title, age
        -> from employee_data ORDER BY
        -> title DESC, age ASC;
        
    +--------+------------+----------------------------+------+
    | emp_id | l_name     | title                      | age  |
    +--------+------------+----------------------------+------+
    |      5 | Anchor     | Web Designer               |   26 |
    |      4 | Pandit     | Web Designer               |   27 |
    |     15 | Gibson     | System Administrator       |   34 |
    |     14 | Lewis      | System Administrator       |   35 |
    |     13 | Hunter     | Senior Web Designer        |   32 |
    |      2 | Hagan      | Senior Programmer          |   32 |
    |      3 | Pillai     | Senior Programmer          |   32 |
    |     16 | Harper     | Senior Marketing Executive |   36 |
    |      8 | Sakamuro   | Programmer                 |   25 |
    |      6 | Kruger     | Programmer                 |   31 |
    |      9 | Nanda      | Programmer                 |   32 |
    |      7 | MacFarland | Programmer                 |   34 |
    |     12 | Hoopla     | Multimedia Programmer      |   32 |
    |     10 | Rajabi     | Multimedia Programmer      |   33 |
    |     11 | Simon      | Multimedia Programmer      |   43 |
    |     18 | Simlai     | Marketing Executive        |   27 |
    |     19 | Irvine     | Marketing Executive        |   27 |
    |     17 | Sehgal     | Marketing Executive        |   30 |
    |     21 | Champion   | Finance Manager            |   36 |
    |     20 | Ali        | Customer Service Manager   |   32 |
    |      1 | Sharma     | CEO                        |   28 |
    +--------+------------+----------------------------+------+
    21 rows in set (0.00 sec)
    
    
    Note: The titles are first sorted in descending order. Then in each title, the ages are further sorted in ascending order.

  4. mysql> SELECT l_name, f_name from employee_data
        -> where title IN ('Programmer',
        -> 'Web Designer') ORDER BY l_name;
    
    +------------+---------+
    | l_name     | f_name  |
    +------------+---------+
    | Anchor     | Mary    |
    | Kruger     | Fred    |
    | MacFarland | John    |
    | Nanda      | Alok    |
    | Pandit     | Anamika |
    | Sakamuro   | Edward  |
    +------------+---------+
    6 rows in set (0.00 sec)